Matematika

Pertanyaan

sin^2 45 + 2cos^2 30 =

2 Jawaban

  • pecah saja menjadi
    sin(45) x sin(45) + 2 x cos(30) x cos (30)

    sin 45 itu [tex] \frac{ \sqrt{2} }{2} [/tex], sedangkan cos 30=  [tex] \frac{ \sqrt{3} }{2} [/tex]

    sehingga menjadi:
    [tex] \frac{ \sqrt{2} }{2} .\frac{ \sqrt{2} }{2} +2\frac{ \sqrt{3} }{2} .\frac{ \sqrt{3} }{2} [/tex]
    [tex] \frac{2}{4} + \frac{6}{4} =2[/tex]
  • sin^2 45 + 2cos^2 30

    sin^2 45
    = (sin 45)^2
    = ( √2/2 ) ^2
    = (2/4)
    = 1/2

    cos^2 30
    = (cos 30)^2
    = (√3/2)^2
    = 3/4

    1/2 + 2 x 3/4
    = 1/2 + 6/4
    = 2/4 + 6/4
    = 8/4
    = 2

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