Suku banyak (2x^3 + ax^2 - bx + 3) di bagi (x2 - 4) bersisa (x + 23) nilai a+b =.....
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Pertanyaan
Suku banyak (2x^3 + ax^2 - bx + 3) di bagi (x2 - 4) bersisa (x + 23) nilai a+b =.....
1 Jawaban
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1. Jawaban mxwotm8
x^2 - 4 = 0
x^2 = 4
x = 2 atau -2
Substitusi :
x = 2
16 + 4a - 2b + 3 = 2 + 23
x = -2
-16 + 4a + 2b + 3 = -2 + 23
4a - 2b = 6
4a + 2b = 34
-2b - 2b = -28
-4b = -28 , b = 7
4a - 7 (2) = 6
4a = 20
a = 5
Nilai a + b = 5 + 7 = 12
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