Sederhanakanlah 9log18 - 9log2

9log18 - 9log2 = [tex] \frac{log 18}{log 9} [/tex] - [tex] \frac{log 2}{log 9} [/tex] = [tex] \frac{log 2 x 3^{2}}{log 3^{2}} [/tex] - [tex] \frac{log 2}{log3^{2}} [/tex] = [tex] \frac{log 2 + log 3^{2}}{2 log 3} [/tex] - [tex] \frac{log 2}{2log 3} [/tex] = [tex] \frac{1}{2} [/tex] [tex] \frac{log2}{log3} [/tex] + [tex] \frac{2log3}{2log3} [/tex] - [tex] \frac{1}{2} [/tex] [tex] \frac{log 2}{log 3} [/tex] = 1

9log18 - 9log2 = 9log(18/2) = 9log9 = 1