Diketahui f(x) = 2x + 8 dan (f o g)(x) = 6x + 10, maka fungsi g(x)

(fog)=6x+10
2g(x)+8=6x+10
2g(x)=6x+10-8
 2g(x)=6x+2
   g(x)=3x+1

f(x) = 2x + 8
(fog)(x) = f(g(x)) = 6x + 10

f(g(x)) = 2(g(x)) + 8

2g(x) + 8 = 6x + 10
2g(x) = 6x + 10 - 8
2g(x) = 6x + 2
g(x) = (6x + 2) /2
g(x) =3x + 1