V.a=72 km/jam V.b=36 km/jam mobil A akan mendahului mobil B. jika massa mobil A 1.600 kg dan massa mobil B 12.800 kg maka perbandingan energi kinetik antara mob

Va=72 km/jam
Vb=36 km/jam
ma=1.600 kg
mb=12.800 kg
dit EK a : EK b
1/2.ma.Va^2: 1/2.mb.Vb^2
Va^2.ma:Vb^2.mb
72^2 . 1600 :36^2 . 12800
5184 . 1600:1296 . 12800
5184:1296 . 8
5184 : 10368
1 : 2

Dik:
va = 72 km/jam = 20 m/s
vb = 36 km/jam = 10 m/s
ma = 1600 kg
mb = 12800 kg

Dit: EKa/EKb

Jawab:

EKa/EKb = (1/2.ma.va^2) / (1/2.mb.vb^2)
EKa/EKb = (ma/mb) . (va/vb)^2
EKa/EKb = (1600/12800) . (20/10)^2
EKa/EKb = (1/8).(4/1)
Eka/EKb = 1/2

Jadi perbandingan EKa : EKb = 1 : 2