akar akar persamaan kuadrat 3ײ-4×-4=0

3x² - 4x - 4 = 0

-6 * 2 = -12
-6 + 2 = -4

maka
x1 = -6/-3 = 2
x2 = 2/-3 = -2/3

3x^2 - 4x - 4 = 0
3x^2 - 6x + 2x - 4 = 0
3x(x - 2) + 2(x - 2) = 0
(3x + 2)(x - 2) = 0

3x + 2 = 0
x = -2/3

x - 2 = 0
x = 2

Akar : -2/3 atau 2