8log 9 =a, 2log 5 =b, dan 7log 2 =c. Nilai 6lig 35 =.....

2log 3= 3a/2
2log 5=b 
7log 2=c
6log 35
= 6log 5 + 6log 7
=[1/(5log 6)] + [1/(7log 6)]
=[1/5log 2 (2log 3+ 2log 2)] + [1/(7log 2 + 7log 3)]
=[1/5log 2 (2log 3+ 1)] + [1/(7log 2 + (7log 2 x 2log 3)]
={b/[(3a/2)+1]}+{1/[c+3ac/2]}
=(bc+1)/c(1+3a/2)