berapa cos dan tangen dari : 120, 150,180,210,240,270,300,330,dan 360 ??

nilai cos :

120 = -\frac{1}{2} [/tex]
150 = -\frac{1}{2} \sqrt{3} [/tex]
180 = -1
210 = - \frac{1}{2} \sqrt{3} [/tex]
240 = - \frac{1}{2} [/tex]
270 = 0
300 = \frac{1}{2} [/tex]
330 = \frac{1}{2} \sqrt{3} [/tex]
360 = 1

nilai tan :

120 = - \sqrt{3} [/tex]
150 = [tex]- \frac{1}{3} \sqrt{3} [/tex]
180 = 0
210 = [tex] \frac{1}{3} \sqrt{3} [/tex]
240 = [tex] \sqrt{3} [/tex]
270 = t.d (tidak terdefinisi)
300 = [tex]- \sqrt{3} [/tex]
330 = [tex]- \frac{1}{3} \sqrt{3} [/tex]
360 = 0

cos 120 = cos (180-60) jadi - cos 60 = -1/2
tan 120 = tan ( 180-60) jadi - tan 60 = -1
cos 150 = cos (180-30) jadi - cos 30 = -1/2√3
tan 150 = tan (180-30) jadi -tan 30 = - 1/3√3
cos 180 = cos (180-0) jadi - cos 0 = -1
tan 180 = tan (180-0) jadi -tan 0 = 0
cos 210 = cos (180 +30) jadi -cos 30 = -1/2√3
tan 210 = tan (180+30) jadi tan 30 = 1/3√3
cos 240 = cos (180+60) jadi -cos 60= -1/2
tan 240 = tan (180+60) jadi tan 60 = 1
cos300 = cos (360-60) jadi cos 60 = 1/2
tan 300 = tan (360-60) jadi -tan60 =-1
cos 330 = cos(360-30) jadi  cos 30 = 1/2√3
tan 330 = tan (360-30) jadi -tan 30 = -1/3√3
cos 360 = cos (360-0) jadi cos 0 = 1
tan 360 = tan (360-0) jadi -tan0 = 0
maap kalo salah~