Matematika

Pertanyaan

abcd = belah ketupat.kelilingnya = 68 cm dan diagonal BD = 16 cm luas belah ketupat abcd adalah.......cm²

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  • keliling belah ketupat = 68
    4s = 68
    s = 68/4 = 17 cm

    panjang diagonal BD = 16 ,(O tengah2 diagonal BD,maka BO = 16/2 = 8 cm)
    panjang diagonal yang lain:
    AO = √17^2 - 8^2
    AO = √289 - 64
    AO = √225
    AO = 15 cm
    AC = AO+OC = 15 + 15 = 30 cm

    L = 1/2 x d1 x d2
    L = 1/2 x 16 x 30
    L = 240 cm^2

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