air bervolume 4 liter bersuhu 80°C dicampur dengan 6 liter air bersuhu 10°C. Berapakah suhu campurannya ? pakai caraaa

Suhu dan Kalor.

ρ = m / V → m = ρV
4 L = 4 x 10⁻³ m³ = (1000 kg/m³)(4 x 10⁻³ m³) = 4 kg
6 L = 6 x 10⁻³ m³ = (1000 kg/m³)(6 x 10⁻³ m³) = 6 kg

Asas Black.
Q lepas = Q terima
m₁c(T₁ - Tc) = m₂c(Tc - T₂)
m₁T₁ - m₁Tc = m₂Tc - m₂T₂
m₁T₁ + m₂T₂ = Tc(m₂ + m₁)
Tc = (m₁T₁ + m₂T₂) / (m₁ + m₂)
    = [(4 kg)(80°C) + (6 kg)(10°C)] / (4 kg + 6 kg) = 38°C