Nilai dari tan^2 210°×sin^2 240°÷cos300°×cot225°=
Matematika
fitrioppo052
Pertanyaan
Nilai dari tan^2 210°×sin^2 240°÷cos300°×cot225°=
1 Jawaban
-
1. Jawaban ariza10
= (1/3√3) x (-1/2√3) : (1/2) x (1)
= (-3/6) : (1/2)
= -3/6 x 2/1
= -6/6
= -1