Matematika

Pertanyaan

lim √2x-2 per √3-2 - √x+2
x=>2

a. -1
b. -1/2
c. 1/2
d. 1
e. 2
pakai cara, makasihh

1 Jawaban

  • [tex]\lim_ {x\rightarrow2} \frac{\sqrt{2x}-2}{\sqrt{3x-2}-\sqrt{x+2}}[/tex]

    [tex]=\lim_ {x\rightarrow2} \frac{(2x)^{\frac12}-2}{(3x-2)^{\frac12}-(x+2)^{\frac12}}[/tex]

    [tex]kita\ pakai\ turunan[/tex]

    [tex]=\lim_ {x\rightarrow2} \frac{\frac22(2x)^{-\frac12}-0}{\frac32(3x-2)^{-\frac12}-\frac12(x+2)^{-\frac12}}[/tex]

    [tex]=\lim_ {x\rightarrow2} \frac{\frac1{\sqrt{2x}}}{\frac3{2\sqrt{3x-2}}-\frac1{2\sqrt{x+2}}}[/tex]

    [tex]=\frac{\frac1{\sqrt{4}}}{\frac3{2\sqrt{6-2}}-\frac1{2\sqrt{2+2}}}[/tex]

    [tex]=\frac{\frac1{\sqrt{4}}}{\frac3{2\sqrt{4}}-\frac1{2\sqrt{4}}}[/tex]

    [tex]=\frac{\frac12}{\frac3{2.2}-\frac1{2.2}}[/tex]

    [tex]=\frac{\frac12}{\frac3{4}-\frac1{4}}[/tex]

    [tex]=\frac{\frac12}{\frac24}[/tex]

    [tex]=\frac{\frac12}{\frac12}[/tex]

    [tex]={\frac12}\times{\frac21}[/tex]

    [tex]=1[/tex]

    semoga membantu, mohon dikoreksi bila ada kesalahan

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