sin 270°.sin 135°.tan225°/sin 150° .sin225°=
Matematika
umarali03
Pertanyaan
sin 270°.sin 135°.tan225°/sin 150°
.sin225°=
.sin225°=
1 Jawaban
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1. Jawaban Anonyme
Bab Trigonometri
Matematika SMA Kelas X
(sin 270° . sin 135° . tan 225°) / (sin 150° . sin 225°)
= (-1 . 1/2 √2 . 1) / (1/2 . (-1/2 √2))
= 1 : 1/2
= 1 x 2/1
= 2