hitunglah 2√3 cos 330° + √3 sin 480° - 1/cosec 60°

= 2[tex] \sqrt{3} [/tex] x 1/2 + [tex] \sqrt{3} [/tex] x ([tex] \sqrt{3} [/tex])/2 - 1/2
= [tex] \sqrt{3} [/tex] + 3/2 - 1/2 = [tex] \sqrt{3} [/tex] + 1

=(2 akar 3 × 1/2 akar 3) + (akar 3 ×1/2 akar 3) - sin 60°
=(2 × 3 × 1/2) + (3 × 1/2) - 1/2 akar 3
= 3 + 3/2 - 1/2 akar 3
= 6 + 3 - akar 3 / 2
= 9 - akar 3 / 2
= 9/2 - akar 3/2