Mohon bantuan nya kak :(

t trapesium
= ½(28-14)=½.14= 7
t trapesium =√25²-7²=√625-49=√576=24 cm
L daerah yang diarsir =
L trapesium - L ½ lingkaran =
(½×(a+b)×t) - (½×phi×r²)=
(½×(14+28)×24)-(½×22/7×7×7)=
(½×42×24)-(11×7)=
(42×12)-77=
504-77=
427 cm²

t² = 25² - [(28 - 14)/2]²
t² = 25² - 7²
t² = 625 - 49
t² = 576
t = √576
t = 24

L trapesium = 1/2 × (a + b) × t
= 1/2 × (14 + 28) × 24 cm²
= 42 × 12 cm²
= 504 cm²

L 1/2 lingkaran = 1/2 × π × r²
= 1/2 × 22/7 × 7 × 7 cm²
= 77 cm²

Luas diarsir = 504 cm² - 77 cm²
= 427 cm²