tolong yaa pakai caraa

g(x) = 3x - 4
y = 3x - 4
y + 4 = 3x
x = (y + 4) / 3
g^-1(x) = (x + 4) / 3

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f(x) = x^3
y = x^3
x = ^3 √y (akar pngkt 3 dr y)
f^(-1)(x) = ^3 √x


(g^-1 o f^-1)(8)
= g^-1 ( f^-1(8))
= g^-1 ( ^3 √8)
= g^-1 (2)
= (2 + 4) /3
= 6/3
= 2

f(x) = x^3, g(x) = 3x - 4
(f o g)(x) = f(g(x)) = f(3x - 4) = (3x - 4)^3
(3x - 4)^3 = y
3x - 4 = y^1/3
3x = y^1/3 + 4
x = 1/3 (y^1/3 + 4)
(f o g)^-1(x) = 1/3 (x^1/3 + 4)
(g^-1 o f^-1)(x) = 1/3 (x^1/3 + 4)
(g^-1 o f^-1)(8) = 1/3 (8^1/3 + 4)
= 1/3 (2^3(1/3) + 4)
= 1/3 (2 + 4)
= 1/3 (6)
= 2