bantu aku jawabin dong kak , aku bawa besok please

1.
n = 2.000 kali
r = 35 cm
keliling = 2 x 22/7 x 35 = 220 cm
Panjang lintasan  = n x K
P = 2.000 x 220 cm = 440.000 cm = 4,4 km

2. Limas alas persegi
keliling alas = 96
4 s = 96
s = 24 cm
tinggi limas = 35 cm
tinggi segitiga bidang tegak = t = √(35²+ 12²) = 37

Luas limas =  luas alas + 4 x luas bidang tegak
LL = 24x24 + 4 (1/2)(24)(37)
LL = 576 + 1.176 = 2.352 cm²

3.
BC = 35
<BOC = 70
<AOB = 40
AB = 40/70 x 35 cm = 20 cm

4. ΔLKO siku siku  di K
OK = 5, KL = 12
OL = √(OK²+KL²) = √(5²+12²) = √169
OL = 13 cm

5. R1 = 15
R2 = 5
Jarak = 26
panjang garis singgnung luar PGSL

PGSL = √26² -(15-5)² = √(676 - 100) = √576
PGSL = 24 cm