Diketahui f(x)=2x-5/2x+1 dan x ≠ -1/2 tentukan f1(0) tolong jawab pake caranya butuh

Turunan

f(x) = (2x-5)/(2x+1)
misal
u = 2x - 5 --> u' = 2
v = 2x +1 ---> v' = 2

f' (x)= u'v - uv' / v²

f '(x) = {2(2x+1) - 2(2x-5)} / (2x+1)²
f ' (0) = { 2(0+1) - 2(0-5)} /{0+1)²
f ' (0) = (2(1) - 2(-5))/ (1)
f' '(0) = (2+10) = 12