Tolong Nomor 4a doang

Bab Differensial
Matematika SMA Kelas XI

f(x) = (x² - 3x) / (x² + 2x + 1)
f'(x) = ((2x - 3) (x² + 2x + 1) - (x² - 3x) . (2x + 2)) / (x² + 2x + 1)²
f'(x) = (2x³ + 4x² + 2x - 3x² - 6x - 3 - 2x³ - 2x² + 6x² + 6x) / (x² + 2x + 1)²
f'(x) = (5x² + 2x - 3) / (x² + 2x +1)²

f'(2) = (5 . 2² + 2 . 2 - 3) / (2² + 2 . 2 + 1)²
f'(2) = (20 + 4 - 3) / (4 + 4 + 1)²
f'(2) = 21 / 81
f'(2) = 7 / 27