tentukan persamaan garis jika(4,3) (-2,6)

y-y1/y2-y1 = x-x1/x2-x1
y-3/6-3 = x-4/(-2)-4
y-3/3 = x-4/-6
-6(y-3) = 3(x-4)
-6y+18 = 3x-12
3x +6y - 12+18 = 0
3x +6y +6 = 0
atau
x+2y +2 = 0
atau
x+2y = -2

Bab Persamaan Garis
Matematika SMP Kelas VIII

(y - y1) / (y2 - y1) = (x - x1) / (x2 - x1)
(y - 3) / (6 - 3) = (x - 4) / (-2 - 4)
(y - 3) / 3 = (x - 4) / -6
** -6 : 3 = -2 **

-2y - 6 = x - 4
x + 2y = -6 + 4
x + 2y = -2
x + 2y + 2 = 0