lim x->2 (2x^2+1) (x-3)= lim x->2 ( x^2-3x+2) / (x-2)= lim x->-4 (x^2-16) / (x+4)= tlg bntu jwbnnya yg bisa..

1. langsung aja masukin nilai x nya ke persamaan
(2(2)^2 +1)(2-3) = (2(4)+1) (-1) = 9(-1) =-9
2. dijabarkan dulu jd (x-2)(x-1)/(x-2) trus x-2 nya dicoret jd sisa x-1.
masukin nilai x=2.
x-1 = 2-1 = 1
3. dijabarkan dulu jd (x+4)(x-4)/(x+4). trus x+4nya bisa dicoret.
masukin nilai x=-4
x-4 = -4 -4 = -8