tolong bantu jawab Makasih

(125/25)^3 = 5^9/5^6 = n

n-(n/5) = (5n/5)-(n/5) = (5/5)(5^9/5^6)-(1/5)(5^9/5^6) = (5^10-5^9)/5^7 = (5^9(5-1))/5^7 = 5^2(4) = 100