fungsi f ditentukan f(x) = 2x+1/x-3 , x tidak sama dengan 3, jika f^-1 invers dri f, maka f^-1(x+1) = ?

f-1(x) = (3x + 1)/(x - 2)

f-1(x + 1) = (3(x + 1)+1)/(x + 1 - 2)
f-1(x + 1) = (3x + 4)/(x - 1)

y = 2x + 1 / x - 3
y ( x-3)= 2x+1
xy-3y = 2x+1
xy-2x = 3y+1
x(y-2)= 3y+1
x = 3y + 1 / y-2
f-¹(x) = 3x + 1 / x-2
maka
f-¹(x+1)= 3(x+1) + 1 / x+1-2
= 3x + 4 / x - 1