ada yg bisa bantu jawab.? Luas daerah yg dibatasi oleh parabola y = 6x - x² dan y = x² - 2x adalah...?

6x - x^2 = x^2 - 2x
2x^2 - 8x = 0

D = (-8)^2 - 4(2)(0) = 64

L = DakarD/2a
L = 64×akar64/2×2
L = 64×8/4
L = 64×2
L = 128 satuan luas

Luas Daerah = [tex]\frac{D \sqrt{D} }{6 a^{2} } [/tex]
D = b² - 4ac

y1 = 6x - x²
y2 = x² - 2x
y1 = y2
6x - x² = x² - 2x
0 = 2x² - 8x
a = 2
b = -8
c = 0
D = (-8)² - 4(2)(0)
D = 64
L = [tex] \frac{64 \sqrt{64} }{6(2)^{2} } [/tex]
L = [tex] \frac{512}{24} [/tex]
L = [tex] \frac{64}{3} [/tex]
L = [tex]21 \frac{1}{3} [/tex] Satuan Luas