Sepotong kayu terapung tiga per lima bagian tercelup didalam air, jika massa jenis air 1x10³ kg/m³ maka massa jenis kayu sebesar?

vbf=1/5 vb
pf = 1000 kg/m^3

pf.vbf = pb.vb
pb = pf.vbf/vb
pb = 1000.vb/5/vb
pb = 1000 vb/5
pb = 200 kg/m^2

semoga membantu

FLUIDA STATIS
• Hk Archimedes

Vt = (3/5) V
ρa = 10³ kg/m³
ρb = __?

massa jenis benda
ρb = (Vt / V) × ρa
ρb = ( (3/5)V / V) × (1000 kg/m³)
ρb = 3/5 × (1000 kg/m³)
ρb = 600 kg/m³ ← jwb ✓