jika f(x)=x²+x+1 dan (fog)(x)= x²+3x+3 fungsi g(2x-3)=

f(x)=x²+x+1 dan (fog)(x)= x²+3x+3 
f(g(x)) = (g(x))² + g(x)  = x² + 3x + 2
x² + 3x + 2 = x² + 2x + x + 1 + 1 
 x² + 2x + 1 + x + 1 
(x+1)² + (x+1) = (g(x))² + g(x) 
g(x) = x+1 
g(2x-3) = 2x-3+1 = 2x-2 
math is easy 

Mapel : Matematika
Kelas : X SMA
Bab : Fungsi Komposisi dan Fungsi Invers

Pembahasan :
Fog(x) = f(g(x))
x² + 3x + 3 = [g(x)]² + [g(x)] + 1
x² + 3x + 2 = [g(x)]² + [g(x)]
(x + 1)² + (x + 1) = [g(x)]² + [g(x)]

g(x) = x + 1
g(2x - 3) = 2x - 3 + 1
g(2x - 3) = 2x - 2