Jika f(x)=x-2 ; g(x)=x2+1 dan h(x)=3x ; hitunglah nilai dari (hogof)(3)

(h o g o f)(x) = h(g(f(x)))
g(f(x)) = g(x-2) = (x-2)² + 1
g(f(x)) = x² - 4x + 4 + 1 = x² - 4x + 5

h(g(f(x))) = h(x² - 4x + 5)
= 3(x² - 4x + 5) = 3x² - 12x + 15

(h o g o f)(3) = 3×9 - 12×3 + 15
= 27 - 36 + 15 = 6