Suku banyak x4+ax3+2x²+bx+6 jika di bagi x+3 bersisa 6 sedangkan jika di bagi x-2 akan bersisa 83. nilai a2+2a+1=

x + 3 = 0
x = -3
f(-3) = 6
-3⁴ + a(-3)³ + 2(-3)² + b(-3) + 6 = 6
81 - 27a + 18 - 3b = 0
-27a - 3b = -99 |÷-3| => 9a + b = 33 |×2| =>
18a + 2b = 66
x - 2 = 0
x = 2
f(2) = 83
2⁴ - a(2)³ + 2(2)² + b(2) + 6 = 83
16 + 8a + 8 + 2b = 83-6
8a + 2b = 77-24
8a + 2b = 53
eliminasi
18a + 2b = 66
8a + 2b = 53
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10a = 13
a = 1,3
a² + 2a + 1 = (1,3)² + 2(1,3) + 1
= 1,69 + 2,6 + 1
= 5,29