Diketahui f(x) = 2x + 8 dan (f o g)(x) = 6x + 10, maka fungsi g(x

(Fog)(x)=F(g(x))
F(g(x))=2x+8
F(g(x))=2(g(x))+8

2g(x)+8=6x+10
2g(x)=6x+10-8
g(x)=6x+2/2
g(x)=3x+1

(fog)(x) = f(g(x))
6x+10 = 2(g(x))+8
6x+10-8 = 2g(x)
6x+2 = 2g(x)
g(x) = (6x+2)÷2
g(x) = 3x+1